½ðÊÀºÀ

  • ½ðÊÀºÀ¡¤(ÖйúÇø)ÓÐÏÞ¹«Ë¾¹ÙÍø
    ½ðÊÀºÀ¡¤(ÖйúÇø)ÓÐÏÞ¹«Ë¾¹ÙÍø

    35kV¼°ÒÔÏÂÓͽþʽµçÁ¦±äѹÆ÷

    Ó¦ÓÃÁìÓò

    ²úÆ·ÌØÕ÷

    ²úÆ·ÁÁµã

    ½ðÊÀºÀ¡¤(ÖйúÇø)ÓÐÏÞ¹«Ë¾¹ÙÍø

    Ó¦ÓÃÁìÓò

    • µçÁ¦ÊäÅäϵͳ
    ½ðÊÀºÀ¡¤(ÖйúÇø)ÓÐÏÞ¹«Ë¾¹ÙÍø

    ²úÆ·ÌØÕ÷

    • ÓͽþʽµçÁ¦±äѹÆ÷ÊÇÒ»ÖÖÒÔ¿óÎïÓÍΪ¾øÔµÏµÍ³µÄµçÁ¦±äѹÆ÷£¬£¬£¬ £¬£¬£¬£¬µçѹƷ¼¶Îª35kVÒÔÏ£¬£¬£¬ £¬£¬£¬£¬²úÆ·ÈÝÁ¿¹æÄ£Îª30-31500kVA£¬£¬£¬ £¬£¬£¬£¬ÓÍÏä´¦Öóͷ£¹¤ÒÕ¿ÉÒÔÖª×ãÒ±½ð¡¢Ê¯»¯ÏµÍ³¼°ÊªÈóëçÅHµØÇøµÄÌØÊâ»§ÍâʹÓÃÒªÇó
    ½ðÊÀºÀ¡¤(ÖйúÇø)ÓÐÏÞ¹«Ë¾¹ÙÍø

    ²úÆ·ÁÁµã

    • ÌúÐĽÓÄÉÓÅÖÊÀäÔþ¾§Á£È¡Ïò¹è¸ÖƬ£¬£¬£¬ £¬£¬£¬£¬¶à¼¶ÐÍ45¡ãȫб½Ó·ìµþ»ý¶ø³É
    • ²úÆ·ÔËÐпÕÔØÏûºÄ¡¢¸ºÔØÏûºÄµÍ
    • ½ÓÄÉԲͲʽ½á¹¹£¬£¬£¬ £¬£¬£¬£¬ÔÑÆ½ºâºÃ£¬£¬£¬ £¬£¬£¬£¬¿¹¶Ì·¹¥»÷ÄÜÁ¦Ç¿
    • Õæ¿Õ×¢ÓÍ, È«ÃÜ·âÐͽṹ£¬£¬£¬ £¬£¬£¬£¬ÌáÉýÄÚ²¿¾øÔµÐÔÄÜ£¬£¬£¬ £¬£¬£¬£¬½µµÍ¾øÔµÓ͵ÄÀÏ»¯£¬£¬£¬ £¬£¬£¬£¬ÑÓÉìʹÓÃÊÙÃü£¬£¬£¬ £¬£¬£¬£¬ïÔÌ­¾Ö²¿·ÅµçÁ¿
    • ½ÓÄɾßÓе¯ÐÔÁ¿µÄ²¨ÎÆÓÍÏä»òƬʽɢÈÈÆ÷£¬£¬£¬ £¬£¬£¬£¬Öª×ã¾øÔµÓÍÈÈÕÍÀäËõµÄÌå»ýת±ä
    • ÏäÍâÍâò¾­È¥Ð⡢ȥÓÍ¡¢Á×»¯´¦Öóͷ£ºóÅçÍ¿µ×Æá¡¢ÃæÆá£¬£¬£¬ £¬£¬£¬£¬¿ÉÒÔÖª×ãÒ±½ð¡¢Ê¯»¯ÏµÍ³¼°ÊªÈóëçÅHµØÇøµÄÌØÊâ»§ÍâʹÓÃÒªÇó
    • Ãâά»¤£¬£¬£¬ £¬£¬£¬£¬ÎÞÐèÌæ»»¾øÔµÓÍ
    ÍøÕ¾µØÍ¼